(5/x)+(x/x+4)=(16/x^2+4x)

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Solution for (5/x)+(x/x+4)=(16/x^2+4x) equation: 



(5/x)+(x/x+4)=(16/x^2+4x)

We move all terms to the left:

(5/x)+(x/x+4)-((16/x^2+4x))=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x+4)!=0

x∈R





Domain of the equation: x^2+4x))!=0

x∈R



We add all the numbers together, and all the variables

(+5/x)+(x/x+4)-((16/x^2+4x))=0

We get rid of parentheses

5/x+x/x-((16/x^2+4x))+4=0

Fractions to decimals

5/x-((16/x^2+4x))+4+1=0

We calculate fractions

We do not support expression: x^3

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